uses const char array in snprintf in c

I'm very new comer to C. I've this type of code and when I tried to execute it this warning message showed up "passing argument 1 of 'snprintf' discards 'const' qualifier from pointer target type" and nothing happened. What I did wrong? Thank yo

How to convert int to char * in C (without sprintf)

some day, i wanted to convert in C an integer into a char *, this int can be negative. I wasn't able to use sprintf ,snprintf neither, so how do i do that ?To roll one's own itoa()-like function, first one must address how to handle memory. The easie

printf and% s in C

I understand that this code segment is supposed to have a buffer overflow vulnerability problem: printf("File %s", my_file_name); printf("File %s"); However, I don't get exactly why it is considered risky. Would anyone be able to shed

Why is printf (inputString) a security hole?

I was reading an answer on Quora where I encountered that something as simple as: char* inputString; printf(inputString); is a security hole. I assume that the inputString is not simply uninitialized, but initialized with some external input between

Unrecognized behavior of pointers

#include<stdio.h> int main() { char str[]={'1','2','3'},*p; p=str; printf("%c",p); return 0; } [email protected] Shouldn't it print 1 or %c might be the reason?To print the value at a pointer (i.e., 1, as you had expected), you got to dereference

Does printf () change its settings?

I was trying to see how different languages handle floating point numbers. I know that there are some inherent issues in floating point representation, which is why if you do 0.3 + 0.6 in Python, you get 0.899999 and not 0.9 However, these snippets o

bash: pass format information in printf

Iv'e got a script with a generalized usage/error function, that prints the error out and then gives the script usage information. I reduced that for purposes of discussion to this example: usage() { test -n "$1" && printf "\n %s&quo

Can I print -0.000 as 0.000?

printf("%.3lf\n", -0.0001); This outputs -0.000, but shouldn't it be 0.000? How can I make this print without the minus sign, i.e. 0.000 ?The correct answer has already been given. Just wanted to add that you'll get the same from c++ cout If you

Format e in printf () and precision modifiers

Could you explain me why line: printf("Value %2.2e ", 1201.0); give a result: Value 1.20e+03 not just a 12.01e2? My way of thinking: default number is 1201.0, specifier tells are that there should be 2 numbers after the digit. Please explain me

Checking output errors in C and C ++

I wrote this simple program. I know that the printf() function in C returns the total number of characters successfully printed so the following C program works fine because any non-zero value is evaluated as true in C. #include <stdio.h> int main(v

Output formatted with variable spacing

Is there a feature that supports using a variable in the flag of javas printf method, for example printf("%nd", 12); where n is a variable? I want to specify spacing outside of the printf method, for example int n = 5; System.out.printf("%n

Reads a line break at the end of the user's entry in c

So, I am trying to read user input using getline and the error I am having is that, if the user enters "Hi there", when it reads this it thinks there is a line break at the end. So when I try to print it, it prints "Hi there" and then

Escape all special characters in printf ()

Is there an easy way to escape all special characters in the printf() function? The reason why I would like to know how to do this is because I am printing a number of characters which may include special characters such as the null character (\0) an

Printf print C ++ double reads like 0

So I want to use printf so that I can make columns line up but printf can't seem to print doubles that need scientific notation. It just comes out as a 0 but with cout it comes out fine. 'in' and 'fn' are structs 'x' 'y' and 'z' are doubles Code prin

C program strange behavior of printf

I'm doing a simple implementation of the UNIX wc command, and I have a very strange problem. If I remove the printf on line 49, the program doesn't work properly. I tried many things, but none of them worked. The program works, but the output is not

Printf behavior by passing fewer arguments

I have just noticed a different behavior of printf function by changing the no. of arguments and the format specifiers. Please take a look on the following code : #include<stdio.h> void main() { int ji=65; printf("ji>=65 ? %d : %c",ji);

printf causes a crash

#include <stdio.h> int main(char sendbuf[100]) { printf (sendbuf); return 0; } Somehow this very basic program crashes when I try to use it, it's meant to print up whatever is typed as a parameter. If I remove the line "printf (sendbuf);"

bash variable as width of field awk

I have a variable: n=$maxlen, is there any way I can use that as the field width when using printf in awk? Something like this: n=$maxlen awk -v val=$n -F',' '{printf "%vals %7s %17s %4i\n", $1, $2, $3, $4}' somefile.txt Figured it out! :D n=$ma

Why does stdout printing not occur when using fprintf?

I have this code: #include <stdio.h> #include <unistd.h> int main() { while(1) { fprintf(stdout,"hello-out"); fprintf(stderr,"hello-err"); sleep(1); } return 0; } The output is hello-err hello-err hello-err hello-err hello-

trying to print a line a text file in c

i am trying to print a line from a text file then go to the next line and print that until there is no more lines left to print. This is what i have so far, but it only works the first time that i run the program. void ReadFile(FILE *a) { char line[2

redirect the output to compressed format (C)

Is it possible to use fprintf in such a way that write data to a compressed file? For example: fopen ("myfile.txt","w"); will write to a plain text file. So the file size grows very large.You can use zlib to write data to a compressed

Binary representation in C

In C why is there no standard specifier to print a number in its binary format, sth like %b. Sure, one can write some functions /hacks to do this but I want to know why such a simple thing is not a standard part of the language. Was there some design

c ++ _vsnprintf unexpected format string

I have a logging function that takes in a variable number of arguments and uses _vsnprintf to format them. My problem is that when I debug my OCR automation the string it returns is sent to the log, so if the file said something like this: This bitma

Pointer will not work in printf ()

Having an issue with printing a pointer out. Every time I try and compile the program below i get the following error: pointers.c:11: warning: format '%p' expects type 'void *', but argument 2 has type 'int *' I'm obviously missing something simple h

Use fprintf in the memory stream

I have a vc++ method that uses fprintf to write values to a file in the hard disc. I want to change this method so that instead of writing the values to disc, I want to return a pointer to the data. I know in advance the size I have to allocate. Is t

Is there a free implementation of printf for .net?

The problems: I can't use string.Format, I have C style format strings; I can't call the native printf (no P/Invoke); I can't use because of the license, I need something GPL-compat