Function, which returns the next 50 leap years

I need to create a function that would return the next 50 leap years beginning from the next leap year after the input year in R. The problem is that I need to save it as a vector. x <- function(year){ year1 <- year + 205 for(i in year:year1){ if((i

Javascript calculates the same day of the week next year

I have some trouble to calculate the weekday of a given date next year. For example: Tuesday, 19. April 2016 is the given date. Now I would calculate: TUESDAY, 18. April 2017. It is very important that the weekdays are always the same. My problem are

How to validate DateTime for a leap year

I'm working with C# and I'm trying to find whether the given date and month is valid for a leap year. This is my code: static void Main(string[] args) { Console.WriteLine("The following program is to find whether the Date and Month is Valid for an LE

Having problems detecting the leap year

avHi again, thank you all for the help in my previous problem. However now i have encountered another problem int main () { int inputSeconds,seconds, minutes, hours , days ,years ; int remainingSeconds ; int current_year = 1970; int current_month = 1

Printing two integers

This could be simple but i just can't get around it at the moment practice question. I'm just trying to print a few integers together so that output would be 2004 is a leap year 2013 is not a leap year public class Ex1partA { public static void main(

Find the last day of the year

I am doing a task in which it is required to find the last day of the year by given current date. Like if its 06/Jan/2013 is given to it and it will automatically return the end day of the year. like 31/Dec/2013 I am using many ways like adding the r

How to get the number of days from month and year

I want to get the number of days in the month which the user specifies. I am using this it works for most months except for Feb and leap year. It shows 28 days and not 29. Can you solve this? begin declare @year int declare @month int select @year =

Effectively calculate leap days

Im using the following function to calculate the number of leap days between two years: static int CountLeapDays(int startYear, int endYear) { int Days = 0; while (true) { if ((startYear % 4 == 0 && startYear % 100 != 0) || startYear % 400 == 0) D

JavaScript calculates years and days from the start date

I have date when someone is born, and I need to calculate with JavaScript or jQuery or so, how many years, days since birth date, until now. So result can be like 20 years, 89 days. I need to have same results as Wikipedia does with their function of

Leap year processing in Python

I have a program where the user enters a date and then compares it to another date to see which one comes first. How would I go about writing a code where the user inputs Feb 29 and the program returns Feb 28 instead (since there is no leap year)? Ex

Java calculate the days of the year

Is there a method in any native Java class to calculate how many days were/will be in a specific year? As in, was it a Leap year (366 days) or a normal year (365 days)? Or do I need to write it myself? I'm calculating the number of days between two d

How to find a leap year by programming in C

I made a program using C to find whether the entered year is a leap year or not. But unfortunately its not working well. It says a year is leap and the preceding year is not leap. #include<stdio.h> #include<conio.h> int yearr(int year); void m

What calendar seems to count the days since December 28, 1800?

I have been tasked to read in some data from some weird old system. The system contains many dates but they are all oddly formatted. They are integer numbers ranging from approximately 55,000 to 80,000. I know two dates for certain: 58,112 equals Feb

calculation of the leap year

In order to find leap years, why must the year be indivisible by 100 and divisible by 400? I understand why it must be divisible by 4. Please explain the algorithm.The length of a year is (more or less) 365.242196 days. So we have to subtract, more o