Python: If (user_input) in Dictionary

Having an issue with checking if user input is in a dictionary. Basics of program is there's a shop inventory. The items are stored in a dictionary with corresponding values e.g. {'kettle': 3,.....} Then I want user to write what they want. So if the

I'm trying to use classes with a dictionary with python

class student(object): def __init__(self, name, age, year):, self.age, self.year = name, age, year self.grades=[] self.grade={} print(name,'-------->','Age:',age,'','Year:',year) def set_grades(self,score): self.grades.append(score) def get

C # checking if duplicate in the dictionary

This isn't a duplicate, since I'm using objects as key I'm trying to create a dictionary which checks if the object that's being inserted is a duplicate, and if it is, it'll increase it's value. My dictionary looks like this: Dictionary<Object, int>

Make a list to a dictionary

This question already has an answer here: How to convert list of key-value tuples into dictionary? 3 answers I have a list like this list = [('a', 3418), ('b', 3544), ('c', 1153), ('d', 2155), ('e', 2254), ('f', 2654), ('g', 2982), ('h', 3267), ('i',

PyCharm does not recognize the value type of the dictionary

I have a simple code snippet where I set dictionary values as empty lists: new_dict = {} for i in range(1, 13): new_dict[i] = [] Now, if inside the loop on the next line I would type new_dict[i] and add a dot, I expect PyCharm to show me a list of me

Is there an offline map layer available for Leaflet?

Is there an offline Map layer available for Leaflet? I don't need in detail, but basic geometry would be sufficient.For sure you can set up your own offline map (raster tiles and/or vector shapes). The difficulty or out-of-the-box availability depend

Build dict in loop adds values ​​to bad keys

I have the following code: data = open(filename).readlines() result = {} for d in data: res[d[0:11]] = d Each line in data looks like so and there are 251 with 2 different "keys" in the first 11 characters: 205583620002008TAVG 420 M 400 M 1140 M

get Json values ​​in Scala scala.util.parsing.json.JSON

This question already has an answer here: How to parse JSON in Scala using standard Scala classes? 5 answers I am new in Scala and I want to extract some values from json I have a big json data as a string and I want to extract only review_score valu

How Javascript compares the key of the card

I am using Javascript ES6 features in a node.js application: class pairKey { constructor(x_pos, y_pos) { this._X = x_pos; this._Y = y_pos; } get x() { return this._X; } set x(x_pos) { this._X = x_pos; } get y() { return this._Y; } set y(y_pos) { this

Print the name of the key together with its value

I have a statement which prints a string relating to a chemical and its desired key values, how do I print the key values corresponding key name? def chemByString(chemName,chemicals,priority="echo"): for chemical in chemicals: chemDict = chemica

Python word frequency counter

Struggling with this exercise which must use a dictionary and count the number of times each word appears in a number of user inputs. It works in a fashion, but does not atomise each word from each line of user input. So instead of counting an input

ServiceStack - dictionary for csv

In my project I use ServiceStack to allow user to export data in csv format. It's ServiceStack that makes the job but it always sorts my dictionary by alphabetical and I don't want that. I want that my csv file have his columns in exact order that I

Read all lines of a text file in the python dictionary

Here I have a function that, when I read, only returns the last line. What am I doing wrong? def read(): with open("text.txt","r") as text: return dict(line.strip().split() for line in text) The text file is pretty simple, two columns

Pythonic chain manipulation

How can I do the following in a more efficient python friendly way? first_team= re.sub("Northern", "N", first_team) first_team=re.sub("Western", "W", first_team) first_team=re.sub("Southern", "S"

Dictionary.ContainsKey always returns False

Well i am trying to create a small application that saves some employees Names, Ages as well as salaries. So i decided to use Dictionary in order to set every employee's salary and i came up with that code Code var employeeSalaryDictionary = new Dict

Sampling keys due to their values

I have a dictionary in python with key->value as str->int. If I have to chose a key based on it's own value, then as the value gets larger the key has a lower possibility of being chosen. For example, if key1=2 and key2->1, then the attitude of k

How to turn a dictionary into a string?

params = {'fruit':'orange', 'color':'red', 'size':'5'} How can I turn that into a string: fruit=orange&color=red&size=5 You can do it like this: '&'.join('%s=%s' % (k,v) for k,v in params.items()) If you are building strings for a URL it would