I want to multiply the all the values stored in a dictionary. Can you suggest me the good way of doing that.

```
dict = {'x': [645, 469,456,790,850],
'y': [599, 548],
'z': [653, 672,150,590],
'w': [653, 672,150,590]}
list = []
for i, j in dict.iteritems():
#loop over all key's and get the values out and multiply with 1000
value_ofkey = float(j[0])
list.append = value_ofkey *1000
value_ofkey = float(j[1])
list.append = value_ofkey *1000
```

Firstly do not name your variable as `dict`

as it is a builtin.

Now to solve your problem you can try a list-comprehesion within a dict-comprehension.

```
>>> dic = {'x': [645, 469,456,790,850],
... 'y': [599, 548],
... 'z': [653, 672,150,590],
... 'w': [653, 672,150,590]}
>>> newdic = {key:[i*1000 for i in val] for key,val in dic.items()}
>>> newdic
{'y': [599000, 548000], 'x': [645000, 469000, 456000, 790000, 850000], 'z': [653000, 672000, 150000, 590000], 'w': [653000, 672000, 150000, 590000]}
```

**POST COMMENT EDIT**

You can restrict the required keys using `if`

condition.

```
newdic = {key:[i*1000 if key != 'x' else i for i in val] for key,val in dic.items()}
```

For a number of such keys you can try

```
newdic = {key:[i*1000 if key not in ('x','y') else i for i in val] for key,val in dic.items()}
```

Working

```
>>> newdic = {key:[i*1000 if key != 'x' else i for i in val] for key,val in dic.items()}
>>> newdic
{'y': [599000, 548000], 'x': [645, 469, 456, 790, 850], 'z': [653000, 672000, 150000, 590000], 'w': [653000, 672000, 150000, 590000]}
>>> newdic = {key:[i*1000 if key not in ('x','y') else i for i in val] for key,val in dic.items()}
>>> newdic
{'y': [599, 548], 'x': [645, 469, 456, 790, 850], 'z': [653000, 672000, 150000, 590000], 'w': [653000, 672000, 150000, 590000]}
```