How do I create another function `find_letter`

that will return the row and column of a specific letter? I tried using `if(letter in table):`

but it uses the original table. And if I write `if(letter in create_table()):`

it tells me that the functions are not iterable. I also have no idea how to return the row and column of a given letter.

I gave up on creating a new function to find the row and column so I tried including a code with the `create_table`

function but I am not sure about it.

To find where in your table desired character is, you can just do this. Result is a tuple containing row and column number.

```
def find_character(target_table, character):
for row in range(len(target_table)):
for column in range(len(target_table[row])):
if target_table[row][column] == character:
return row,column
```