How do I create another function
find_letter that will return the row and column of a specific letter? I tried using
if(letter in table): but it uses the original table. And if I write
if(letter in create_table()): it tells me that the functions are not iterable. I also have no idea how to return the row and column of a given letter.
I gave up on creating a new function to find the row and column so I tried including a code with the
create_table function but I am not sure about it.
To find where in your table desired character is, you can just do this. Result is a tuple containing row and column number.
def find_character(target_table, character): for row in range(len(target_table)): for column in range(len(target_table[row])): if target_table[row][column] == character: return row,column