I am trying to retrieve data from mysql database from 5 different table but it did not work as it should and it did not display anything.
tables are :
- site_info
- site_coordinates
- owner_info
- subcontractor_info
- company_info
site_info:
- siteID
- companyID -siteNAME
- ownerID
- subcontractorID
- equipmentTYPE
site coordinates:
siteID
latitude
longitude
height
owner_info:
- ownerID
- ownerNAME
- ownerCONTACT
subcontractor_info:
- subcontractorID
- subcontractorCOMPANY
- subcontractorNAME
- subcontractorCONTACT
company_info:
- companyID
- companyNAME
mysql query:
select
site_info.siteID,site_info.siteNAME ,site_info.equipmentTYPE,site_coordinates.latitude,site_coordinates.longitude,site_coordinates.height ,owner_info.ownerNAME,owner_info.ownerCONTACT,company_info.companyNAME,subcontractor_info.subcontractorCOMPANY,subcontractor_info.subcontractorNAME,subcontractor_info.subcontractorCONTACT
from `site_info`
INNER JOIN `owner_info`
on site_info.ownerID = owner_info.ownerID
INNER JOIN `company_info`
on site_info.companyID = company_info.companyID
INNER JOIN `subcontractor_info`
on site_info.subcontractorID = subcontractor_info.subcontractorID
INNER JOIN `site_coordinates`
on site_info.siteID=site_coordinates.site_id
where owner_info.ownerID = 159
Where is my error, and is there any better way to do it?
I solve it just needed to change to the LEFT JOIN .
so the updated query looks:
select
site_info.siteID,site_info.siteNAME ,site_info.equipmentTYPE,site_coordinates.latitude,site_coordinates.longitude,site_coordinates.height ,owner_info.ownerNAME,owner_info.ownerCONTACT,company_info.companyNAME,subcontractor_info.subcontractorCOMPANY,subcontractor_info.subcontractorNAME,subcontractor_info.subcontractorCONTACT from `site_info`
LEFT JOIN `owner_info`
on site_info.ownerID = owner_info.ownerID
LEFT JOIN `company_info`
on site_info.companyID = company_info.companyID
LEFT JOIN `subcontractor_info`
on site_info.subcontractorID = subcontractor_info.subcontractorID
LEFT JOIN `site_coordinates`
on site_info.siteID=site_coordinates.siteID
where owner_info.ownerID = 159
thank you for your comments and answers