How to extract all characters from a string to isolate integers

advertisements

I am trying to figure out a way to extract all characters from a string ('.',',','abcdefghijklmnopqrstvwxyz', '/','\', etc...) and isolate the digits for instance:

if I have input:

hey.44.6 how a8re you99? -.23 4

My program needs to be able to extract each digit : 44, 6, 8, 99, 23 and 4 then give me the number of integers the string has (this one has 6) and the sum of the numbers.

I am having a really tough time even getting a start to this question, and I've looked at many options including re. If someone could help me even get a handle on this, it would be greatly appreciated.

You can do it with re. Here's one way:

>>> re.findall("[0-9]+", s)
['44', '6', '8', '99', '23', '4']

Related Articles

How to extract a number from a string in Perl?

I have print $str; abcd*%1234$sdfsd..#d The string would always have only one continuous stretch of numbers, like 1234 in this case. Rest all will be either alphabets or other special characters. How can I extract the number (1234 in this case) and s

Removes all characters from variable String but letters

This question already has an answer here: How do I remove all non alphanumeric characters from a string except dash? 9 answers I want to write a function that removes all characters in a string variables but leaves only the letters. For example, if t

Extract only characters from a string in Python

In Python, I want to extract only the characters from a string. Consider I have the following string, input = "{('players',): 24, ('year',): 28, ('money',): 19, ('ipod',): 36, ('case',): 23, ('mini',): 46}" I want the result as, output = "p

How to replace all characters in a string?

I have a string that is passed by parameter and I have to replace all occurrences of it in another string, ex: function r(text, oldChar, newChar) { return text.replace(oldChar, newChar); // , "g") } The characters passed could be any character,