I am trying to figure out a way to extract all characters from a string (`'.'`

,`','`

,`'abcdefghijklmnopqrstvwxyz'`

, `'/'`

,`'\'`

, etc...) and isolate the digits for instance:

if I have input:

```
hey.44.6 how a8re you99? -.23 4
```

My program needs to be able to extract each digit : `44`

, `6`

, `8`

, `99`

, `23`

and `4`

then give me the number of integers the string has (this one has 6) and the sum of the numbers.

I am having a really tough time even getting a start to this question, and I've looked at many options including `re`

. If someone could help me even get a handle on this, it would be greatly appreciated.

You can do it with `re`

. Here's one way:

```
>>> re.findall("[0-9]+", s)
['44', '6', '8', '99', '23', '4']
```