How do I perform an in-place replacement of all occurrences of an item in a list in Python?

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This question already has an answer here:

  • Replace values in list using Python 6 answers

Assume I have a list:

myl = [1, 2, 3, 4, 5, 4, 4, 4, 6]

What is the most efficient and simplest pythonic way of in-place (double emphasis) replacement of all occurrences of 4 with 44?

I'm also curious as to why there isn't a standard way of doing this (especially, when strings have a not-in-place replace method)?


We can iterate over the list with enumerate and replace the old value with new value, like this

myl = [1, 2, 3, 4, 5, 4, 4, 4, 6]
for idx, item in enumerate(myl):
    if item == 4:
        myl[idx] = 44
print myl
# [1, 2, 3, 44, 5, 44, 44, 44, 6]