Delete the empty element but keep the zeros as values

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I have a list as follows:

lst = [-1.33, '', -1.33, -1.33 -2.62, 0, -2.66, 1.41, 0, 0, 1.40, '',  1.37, 0]

where there are two empty elements '' in the list with several zeroes and float numbers.

How can I remove the empty elements but keep the zeroes? as follows...

lst2 = [-1.33, -1.33, -1.33 -2.62, 0, -2.66, 1.41, 0, 0, 1.40, 1.37, 0]

I have tried the following:

lst2 = filter(None, lst)

and

lst2 = [x for x in lst if x if isinstance(x,str) == False]

but, it removes the zeroes as well.

I know floats return 12 decimal places, please ignore for example purposes.

Any advice? Thanks.

Why not simply remove all '' ?

>>> lst2 = [x for x in lst if x != '']
>>> lst2
[-1.33, -1.33, -3.95, 0, -2.66, 1.41, 0, 0, 1.4, 1.37, 0]
>>>

or you could keep only floats and ints:

>>> [x for x in lst if isinstance(x, (float, int))]
[-1.33, -1.33, -3.95, 0, -2.66, 1.41, 0, 0, 1.4, 1.37, 0]

# or a bit fancier
>>> import numbers
>>> [x for x in lst if isinstance(x, numbers.Number)]
[-1.33, -1.33, -3.95, 0, -2.66, 1.41, 0, 0, 1.4, 1.37, 0]

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